Asked by Summer

MnO4^– + SO3^2– + H2O → MnO2 + SO4^2– + OH^–

If the reaction occurs in an acidic solution where water and H+ ions are added to the half-reactions to balance the overall reaction, how many electrons are transferred in the balanced reduction half-reaction?

The answer I got is 3*2 which equals 6.

Answers

Answered by bobpursley
Mn goes from +7 to +4 : gained three.
S goes from +4 to +6: lost two
O is unchanged
H is unchanged
so above total is six, once you balance electrons. (2Mn, 3S)
Answered by DrBob222
Howefer, I'm having trouble with this problem because in an acidic solution KMnO4 goes to Mn^2+ and not MnO2.
Answered by Summer
I noticed that as well, Dr. Bob. I'm not quite sure why my teacher has it set up this way.
Answered by @ Summer--DrBob222
Thank you for clearing this up. So it isn't a typo. I suspect your teacher just goofed with the problem. As it stands, however, it isn't possible to answer the question becasue the question is flawed..
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