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Uninhibited Growth Model. This is an example problem from the book and need help figuring it out? a) If $3500 is invested in an...Asked by Adamm
Uninhibited Growth Model. This is an example problem from the book and need help figuring it out?
a) If $3500 is invested in an account that pays 5% interest compounded continuously, how long will it take to grow to $7000.
b) How much money will the account be worth in 20 years.
a) If $3500 is invested in an account that pays 5% interest compounded continuously, how long will it take to grow to $7000.
b) How much money will the account be worth in 20 years.
Answers
Answered by
MsPi_3.14159265
http://www.onlinecalculatorfree.org/law-of-uninhibited-growth-calculator.html#.WsHVGDMh02w
I found this free calculator on-line.
I saw your question earlier in the day but was unable to help you.
I found this free calculator on-line.
I saw your question earlier in the day but was unable to help you.
Answered by
Reiny
As MsPi's webpage shows the general formula for continuous growth is
amount = principal e^(kt), where k is the perodic rate as a decimal and t is the number of periods (in most cases the period is in years, like in your question)
3500 e^(.05t) = 7000
e^(.05t) = 2
take ln of both sides and use your log rules
.05t (ln e) = ln 2
.05t = .693147...
t = appr 13.9 years
for the second part simply replace t = 20 in the formula
amount = principal e^(kt), where k is the perodic rate as a decimal and t is the number of periods (in most cases the period is in years, like in your question)
3500 e^(.05t) = 7000
e^(.05t) = 2
take ln of both sides and use your log rules
.05t (ln e) = ln 2
.05t = .693147...
t = appr 13.9 years
for the second part simply replace t = 20 in the formula
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