Question

Is this correct

How many grams of C2H5OH are used up when 6.25 grams of O2 react according to the following equation?
C2H5OH + 3O2 → 2CO2 + 3H2O


6.25 grams of O2
6.25 / 32 moles = .195 moles

The equation requires 1 mole of C2H5OH for every 3 moles of O2.
1/3 of .195 moles of C2H5OH will be used = .065 moles.
The molecular weight of C2H5OH is 2*14 + 6*1 + 1 *16 = 50
.065 moles is 3.25 grams.
bobpursley
correct.

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