Question
Iron fluoride (FeF2) dissociates according to the following equation:
FeF2(s) ⇌ Fe^2+(aq) + 2 F^–(aq)
A sample of iron fluoride (FeF2) is dissolved in water, and a saturated solution is obtained. The [Fe^2+] is measured to be 2.05 × 10^–4 mol/L.
What is the concentration of fluoride (F^–) ions?
FeF2(s) ⇌ Fe^2+(aq) + 2 F^–(aq)
A sample of iron fluoride (FeF2) is dissolved in water, and a saturated solution is obtained. The [Fe^2+] is measured to be 2.05 × 10^–4 mol/L.
What is the concentration of fluoride (F^–) ions?
Answers
bobpursley
It has to be twice that.
Madison
It's not 2.05 x 10^-4 mol/L
Bobpursley has to be right it must be double!
Bobpursley has to be right it must be double!
uwu binch
the peeps above me r right! just do wha dey say:
(2.05 × 10^–4) x 2 = 4.10 × 10^–4 mol/L
hope dis helps <3
(2.05 × 10^–4) x 2 = 4.10 × 10^–4 mol/L
hope dis helps <3