Question
A bullet of mass 0.1kg is moving at a speed of 300m/s is beds in ablock of mass 4kg initially at rest on frictionless horizontal surface as shown below.the block is attached to aspring of k is 200n/m.what is the maximum compression of the spring?
Answers
Help me
.1 * 300 = 4.1 v
v = 7.32 m/s
Ke = (1/2) m v^2 = (1/2)(4.1)(7.32)^2 = 110 Joules
110 Joules = (1/2) k x^2
v = 7.32 m/s
Ke = (1/2) m v^2 = (1/2)(4.1)(7.32)^2 = 110 Joules
110 Joules = (1/2) k x^2
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