Question

Zinc fluoride (ZnF2) dissociates according to the following equation:

ZnF2(s) ⇌ Zn2+(aq) + 2F–(aq)

Ksp of this equilibrium is 3.0 × 10–2.

If the concentration of zinc ions (Zn2+) in a solution is measured to be 4.4 × 10–1 M, what is the concentration of the fluoride ions (F–)?

Answer 1

Ksp = (Zn^2+)(F^-)^2. You know Ksp and Zn^2+, solve for F^- but this works ONLY i the solution is saturated with ZnF2.

Answer 2

2.6 x 10^-1 hope dis helps