Question
The question wants me to find sin(x/2) when cosx = -(12/13) in the interval (pi,3pi/2). I know that the eventual answer will be 5/sqrt26, however, I am not sure how to get there.
Answers
the interval is Quad III , so x/2 will be in Quad II
sin(Θ/2) = ± √{[1 - cos(Θ)] / 2}
sin(Θ/2) = ± √{[1 - cos(Θ)] / 2}
Related Questions
Solve this equation fo rx in the interval 0<=x<=360
3sinxtanx=8
I would do it this way:
sinxtan...
I have a question relating to limits that I solved
lim(x-->0) (1-cosx)/2x^2
I multiplied the num...
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).
8. cos2x=cosx
10...
find absolute max and min of f(x)=cosx+sin^2(x) on interval [0,2pi]. Give exact answers, not decimal...