Asked by Jade

Given:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMN

Answers

Answered by Steve
What purpose does Q serve?
Answered by A-343479
Given:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMNGiven:
LM

KN
,
KL

NM

LP = h­1 = 5 cm, MQ = h2 = 6 cm
PKLMN = 42 cm
Find: Area of KLMN
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