Asked by Issaya
If a body of 4.5kg falls freely from rest for 2seconds before it strike the ground. Calculate the maximum kinetic energy a body will gain
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Answered by
Anonymous
If this is near earth surface then g = about 9.8 m/s^2
v = a t = 9.8 * 2 = 19.6 m/s
Ke = (1/2) m v^2 = (1/2)(4.5)(19.6)^2 Joules
v = a t = 9.8 * 2 = 19.6 m/s
Ke = (1/2) m v^2 = (1/2)(4.5)(19.6)^2 Joules
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