Asked by Liz
Find the first three iterates of the function f(x)=x^2-2, if the intial value is -2.
z(0)=-2
z(1)=(-2)^2-2 or 4-2=2
z(2)=(2)^2-2 or 4-2=2
z(3)=(2)^2-2 or 4-2=2
Answer: z(1)=2, z(2)=2, z(3)=2
z(0)=-2
z(1)=(-2)^2-2 or 4-2=2
z(2)=(2)^2-2 or 4-2=2
z(3)=(2)^2-2 or 4-2=2
Answer: z(1)=2, z(2)=2, z(3)=2
Answers
Answered by
bobpursley
correct.
Answered by
Liz
Thanks