Asked by lester
a 3300 mf capacitor recquired to store 0.5mj of the energy.find the potential difference to which the capacitor must be charged?
Answers
Answered by
Arora
Energy stored in a capacitor = E = (1/2)*C*(V^2)
=> V = √((2*E)/C)
As per the question,
E = 5 * 10^-4 J
C = 3.3 * 10^-3
Plug in the values to get 'V'
=> V = √((2*E)/C)
As per the question,
E = 5 * 10^-4 J
C = 3.3 * 10^-3
Plug in the values to get 'V'
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