Asked by Fred
5x / x^2+1 less then or equal to x. Please someone help help been stuck on it for a while and I have an exam tommorrow. Any help is greatly appreciated
Answers
Answered by
Arora
If you mean: (5x) / (x^2 + 1),
Then it depends entirely on what value of 'x' you take.
For x = 0, the two terms are equal.
For x = 1, (5x) / (x^2 + 1) is greater than one.
For x = -1, (5x) / (x^2 + 1) is less than one.
Then it depends entirely on what value of 'x' you take.
For x = 0, the two terms are equal.
For x = 1, (5x) / (x^2 + 1) is greater than one.
For x = -1, (5x) / (x^2 + 1) is less than one.
Answered by
Henry
5x/(x^2+1) <= x.
Multiply both sides by x^2 + 1:
5x<= x(x^2+1),
5 <= x^2 + 1,
4 <= x^2
2 <= X.
X=> 2.
Multiply both sides by x^2 + 1:
5x<= x(x^2+1),
5 <= x^2 + 1,
4 <= x^2
2 <= X.
X=> 2.
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