Asked by Anonymous
The three blocks shown are released from rest and are observed to move with accelerations that have a magnitude of 1.5 m/s^2. Disregard any pulley mass or friction in the pulley and let M = 2 kg.
a) What is the magnitude of the friction force on the block that slides horizontally?
b) What is the tension force between M and 2M?
pulley-----block2M-----pulley
l l
l l
blockM block2M
a) What is the magnitude of the friction force on the block that slides horizontally?
b) What is the tension force between M and 2M?
pulley-----block2M-----pulley
l l
l l
blockM block2M
Answers
Answered by
bobpursley
ok, forces, to the right is +
starting on the left side...
-mg -frictionon2M + 2mg=total mass*acceleration
mg-frictionon2M=(5m)*1.5
frictionon2m=2*9.8-7.5=12.1 N
starting on the left side...
-mg -frictionon2M + 2mg=total mass*acceleration
mg-frictionon2M=(5m)*1.5
frictionon2m=2*9.8-7.5=12.1 N
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