Ask a New Question

Question

Find the first three nonzero terms and the general term of the Maclaurin series generated by e^(-6x).

My answer: 1 + x + (x^2)/2, general term (x^(n-1))/(n-1)!
7 years ago

Answers

Reiny
the expansion is
e^x = 1 + x/1! + x^2/2! + x^3/3! + .... + e^(n-1)x)/(n-1)! + ....
you just stated the first 3 terms and the general term of the general series.

e^(-6x) = 1 + (-6x) + (36x^2)/2 + (-216x^3)/6 + ....
= 1 - 6x + 18x^2 - 36x^3 + ....

general term : e^(n-1)(-6x)/(n-1)!

7 years ago

Related Questions

let m and b be nonzero real numbers if the line y=mx+b intersects y^2=4px in only one point, show... Find a nonzero vector orthogonal to the plane through the points P, Q, and R.? Consider the points b... is the set of nonzero integers closed for multiplication If p and q are nonzero integers, which pair of points must lie in the same quadrant? A. (p, q) and... If j and k are nonzero integers, which pair of points must lie in the same quadrant? (j, j) and (k,... How are graphs with a nonzero axis misleading? 1)they distort differences between values 2)they ar... How are graphs with a nonzero axis most misleading? 1)they are visually distracting 2)they are cre... Let be a nonzero rational number. Is rational or irrational? You can earn 5 coins When a and b are nonzero real numbers, and m is an integer, the exponential expression (a/b)^m is eq...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use