Asked by laura
Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,1) E (7,1) and F(1,5).
can you please explain how i can find this answer? i am having trouble
can you please explain how i can find this answer? i am having trouble
Answers
Answered by
Steve
this might be a good place to start:
https://brilliant.org/wiki/triangles-circumcenter/
You can also work out where the perpendicular bisectors of two of the sides meet.
https://brilliant.org/wiki/triangles-circumcenter/
You can also work out where the perpendicular bisectors of two of the sides meet.
Answered by
scott
the circumcenter is equidistant from all three vertices
it lies on the intersection of the three perpendicular bisectors of the sides
midpoint DF is ... (1,3) ... b DF is ... y = 3
midpoint DE is ... (4,1) ... b DF is ... x = 4
it lies on the intersection of the three perpendicular bisectors of the sides
midpoint DF is ... (1,3) ... b DF is ... y = 3
midpoint DE is ... (4,1) ... b DF is ... x = 4
Answered by
laura
steve
i got -2a + 1 - 2b+1 = 14a+28 + 2b+1 i dont know what to do after
and
14a + 28 - 8b-16 + 2a + 1 - 10b+20 but i dont know what to do after this one too :/
i got -2a + 1 - 2b+1 = 14a+28 + 2b+1 i dont know what to do after
and
14a + 28 - 8b-16 + 2a + 1 - 10b+20 but i dont know what to do after this one too :/
Answered by
Steve
what, you forgot your Algebra I ?
-2a + 1 - 2b+1 = 14a+28 + 2b+1
14a + 28 - 8b-16 = 2a + 1 - 10b+20
kinda messy, so simplify a bit
16a+4b = -27
12a+2b = 9
Now you can use those to solve for a and b, which I assume are the coordinates of the circumcenter.
-2a + 1 - 2b+1 = 14a+28 + 2b+1
14a + 28 - 8b-16 = 2a + 1 - 10b+20
kinda messy, so simplify a bit
16a+4b = -27
12a+2b = 9
Now you can use those to solve for a and b, which I assume are the coordinates of the circumcenter.
Answered by
scott
are we all solving the same problem?
Answered by
laura
I didnt forget i just have trouble understanding as quick and easy as others im not good in math...
but thankyou for helping me.
but thankyou for helping me.