Question

the inside of a glass is in the shape of an inverted cone of depth 8cm and radius 4cm. Wine is poured into the glass at a rate of 4cm^3/s. Find the rate at which the depth of the wine in the glass is increasing when the depth is 6cm.

Thanks

Answer 1

dv/dt = surface area * dh/dt
h=2r, so when h=6, r=3
dv/dt = πr^2 dh/dt