Asked by Shiv
Find an equation for a line that contains (-4, -3) and is parallel to the graph of 2x - 5y = 40
1. y = -2/5 x + 4 3/5
2. y = 2/5 x - 1 2/5
3. y = -5/2x - 13
4. y = 5/2x + 7
1. y = -2/5 x + 4 3/5
2. y = 2/5 x - 1 2/5
3. y = -5/2x - 13
4. y = 5/2x + 7
Answers
Answered by
Steve
2x - 5y = 40 has slope 2/5
So, now you have a point and a slope, so use the point-slope form of the line:
y+3 = 2/5 (x+4)
Now pick the choice which matches that
So, now you have a point and a slope, so use the point-slope form of the line:
y+3 = 2/5 (x+4)
Now pick the choice which matches that
Answered by
Henry
P(-4,-3), m = -A/B = -2/-5 = 2/5.
Y = mx+b.
-3 = (2/5)(-4) + b,
b = ?
Plug the calculated value of m and b into the above equation.
Y = mx+b.
-3 = (2/5)(-4) + b,
b = ?
Plug the calculated value of m and b into the above equation.
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