Asked by Richool m
brenda walks 7km for a bearing of 120degrees then 9km for a bearing of 180degrees.Calculate distance and and bearing?
Answers
Answered by
Richool m
bearing 40degree
distance 46km
distance 46km
Answered by
scott
the bearing has to be between 120º and 180º
she walked 16 km total , so the distance must be less than that
40º and 46 km makes no sense
use N/S and E/W components of each segment of the trip to find the total resultant
she walked 16 km total , so the distance must be less than that
40º and 46 km makes no sense
use N/S and E/W components of each segment of the trip to find the total resultant
Answered by
Henry
D = 7km[120o] + 9km[180o].
X = 7*sin120 + 9*sin180 = 6.06 km.
Y = 7*Cos120 * 9*Cos180 = -12.5 km.
D = 6.06 - 12.5i = 13.9km[-25.9o] = 13.9km[25.9o] S. of E. = 13.9km[103.5o] CW(bearing).
Tan A = X/Y.
X = 7*sin120 + 9*sin180 = 6.06 km.
Y = 7*Cos120 * 9*Cos180 = -12.5 km.
D = 6.06 - 12.5i = 13.9km[-25.9o] = 13.9km[25.9o] S. of E. = 13.9km[103.5o] CW(bearing).
Tan A = X/Y.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.