Asked by RaShawnya
A primary sedimentation tank that has a removal efficiency of 65% and settles out solids from a wastewater that has a SS concentration of 220 mg/L. The wastewater flows into the sedimentation tank at a rate of 2.35 million gallons per day (MGD). How many tons (as dry mass) of primary sludge are produced each day?
The answer is 1.40 tons, but I don't know how to do it.
The answer is 1.40 tons, but I don't know how to do it.
Answers
Answered by
bobpursley
tons=.65*.220g/liter*3.9liters/gal*2.35e6gallons/day*ton/9.06e5 grams=140 tons
those tons are US tons, not metric.
those tons are US tons, not metric.
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