Question

The combustion of 1.014g of benzoic acid brings a temp change of 22.2 to 24.86^0C
During the process the fuse of the bcalorimeter melts from 0.12g to0.010g .with delta H=5857j/g
Find the energy change for the overall process
Combustion of Benzoic acid is given as
C6H5COOH+CO2____CO2+H20 deltaH =26.456kj?g

Answer 1

q(v) = E = [(26,456 kJ/g x 1.014 g)(24,86-22.2)] + [(0.12-0.10)(5.857 Kj/g)(24.86-22.2)] = ?

Answer 2

For the second part do we use delta T, as it is melting and during melting temperature is constant