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Asked by Downer

Bob's age is 4 times greater than Susan's age. Dakota is 3 years younger than Susan. The sum of Bob's Susan's and Dakota's ages is 93 what is Susan's age
7 years ago

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Answered by scott
B + S + D = 93

B = 4S

D = S - 3

substituting ... (4 S) + S + (S - 3) = 93
7 years ago

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