Cost of sausages for parents = $3 x 120 x 1.7 = $612
Cost of sausages for children = $2 x 120 x 2.3 = $552
Total Cost (including cleaning) = $612 + $552 + $300 = $1464
Assume ticket cost for parents to be 'a' and children to be 'b'.
Then, a = 2b
Now, since the ticket price needs to be exactly equal to the cost,
120 (1.7a + 2.3b) = 1464 ;
or, 120 {1.7(2b) + 2.3b) = 1464 ;
or, 3.4b + 2.3b = 12.2;
or, 5.7b = 12.2;
or, b = 2.14
Then, a = 2b = 2 x 2.14 = 4.28
Therefore, tickets will cost $2.14 for children and $4.28 for adults.
A primary school is planning to hold a fete, but needs help in figuring out how much to charge for entry. they intend to have an 'all you can eat' sausages sizzle, and they think each adult will eat about $3 worth of sausages and each child $2 worth. The cost of cleaning after the event will be $300. They want an adult ticket to cost twice as much as a child ticket, and they expect that, on average , 1.7 parents and 2.3 children will come from each family. How much will they need to charge for adult and child tickets if they are expecting 120 families to attend and they don't want to make a porfit or a loss?
1 answer
1 answer