Asked by Dora
The elements X and Y form a compound that is 40% X and 60%Y by mass. The atomic mass of X is twice that of Y. What is the empirical formula of the compound?
Answers
Answered by
Arora
The mass of Y is 1.5 times the mass of X in the compound, as per the percentages.
If both molecules had the same atomic mass, they would also be present in this ratio in the compound.
However, the atomic mass of X is twice that of Y. So, for the same mass, X would have half the number of atoms as Y.
Ratio of atoms of Y to that of X = Ratio of mass given * Ratio of atomic masses
= 1.5 * 2
= 3
Hence, the compound is X(1)Y(3)
If both molecules had the same atomic mass, they would also be present in this ratio in the compound.
However, the atomic mass of X is twice that of Y. So, for the same mass, X would have half the number of atoms as Y.
Ratio of atoms of Y to that of X = Ratio of mass given * Ratio of atomic masses
= 1.5 * 2
= 3
Hence, the compound is X(1)Y(3)
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