Asked by John
An airplane is headed southwest (bearing 225°) with an air speed of 550 miles per hour, with the wind blowing from the northwest (bearing 135°) at a speed of 110 miles per hour. Find the drift angle, ground speed, and the course of the airplane.
Answers
Answered by
Steve
planes fly headings, not bearings.
Turn your data into vectors. Add the vectors, and convert back to speed and heading.
550@225° = <-389,-389>
110@135° = <78,-78>
So, the resultant velocity is <-311,-467> = 561@214°
I'll leave the drift angle up to you. Draw a diagram of the vectors involved.
Turn your data into vectors. Add the vectors, and convert back to speed and heading.
550@225° = <-389,-389>
110@135° = <78,-78>
So, the resultant velocity is <-311,-467> = 561@214°
I'll leave the drift angle up to you. Draw a diagram of the vectors involved.
Answered by
Henry
Vr = 550mi/h[225o] + 110mi/h[135o].
X = 550*sin225 + 110*sin135 = -311.1 mi/h.
Y = 550*Cos225 + 110*Cos135 = -466.7 mi/h.
Vr = -311.1 - 466.7i = 561mi/h[33.7o] = 561mi/h[214o]CW(Bearing) =
Resultant velocity and Direction.
Drift = 225-214 =
X = 550*sin225 + 110*sin135 = -311.1 mi/h.
Y = 550*Cos225 + 110*Cos135 = -466.7 mi/h.
Vr = -311.1 - 466.7i = 561mi/h[33.7o] = 561mi/h[214o]CW(Bearing) =
Resultant velocity and Direction.
Drift = 225-214 =
Answered by
Henry
Note: 33.7o W. of S. = 214o CW from +Y-axis.
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