Asked by George Carl
Find the initial value a, growth/decay factor b, and growth/decay rate r for the following exponential function:
Q(t)=0.0036(2.58)^−4t
a) The initial value is a=
(b) The growth factor is b=
(c) The growth rate is r=
Q(t)=0.0036(2.58)^−4t
a) The initial value is a=
(b) The growth factor is b=
(c) The growth rate is r=
Answers
Answered by
Steve
(a) recall that 2.58^0 = 1
(bc) 2.58^-4 = 0.0225 = 2.25%
(bc) 2.58^-4 = 0.0225 = 2.25%
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