To analyze the two samples, we need to determine how Y changes in relation to X in each sample.
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Sample A changes by a common: factor of 2. Looking at the Y values:
- When X = 0, Y = 2
- When X = 1, Y = 4 (change of 2)
- When X = 2, Y = 8 (change of 4)
- When X = 3, Y = 16 (change of 8)
The pattern shows that as X increases by 1, the Y values are influenced by the previous Y value, effectively multiplying.
However, the exact relation can be seen: \(Y \text{(Sample A)} = 2^X\).
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Sample B changes by a common: factor of 6. Looking at the Y values:
- When X = 0, Y = 8
- When X = 1, Y = 14 (change of 6)
- When X = 2, Y = 20 (change of 6)
- When X = 3, Y = 26 (change of 6)
The Y values increase by a constant amount of 6 as X increases by 1.
Thus, it shows a linear relationship: \(Y \text{(Sample B)} = 6X + 8\).
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When x = 4, both y values will be:
- For Sample A: \[ Y = 2^X \implies Y = 2^4 = 16 \]
- For Sample B: \[ Y = 6X + 8 \implies Y = 6(4) + 8 = 24 + 8 = 32 \]
So, the complete statements are:
- Sample A changes by a common factor of 2 (exponential).
- Sample B changes by a common factor of 6 (linear).
- When X = 4, both Y values will be 16 (Sample A) and 32 (Sample B).