To complete the Punnett square for the given trait of eye color with brown eyes being dominant (T) and blue eyes being recessive (t), we start with the following setup:
\[ \begin{array}{c|c|c} & T & t \ \hline T & TT & Tt \ \hline T & TT & Tt \ \end{array} \]
From the completed Punnett square, we can summarize the genotypes:
- TT: 2 occurrences
- Tt: 2 occurrences
- tt: 0 occurrences
Now, we can assess the probabilities:
-
Percent chance of genotype TT:
- Number of TT = 2
- Total = 4
- Probability = (2/4) * 100% = 50%
-
Percent chance of genotype Tt:
- Number of Tt = 2
- Total = 4
- Probability = (2/4) * 100% = 50%
-
Percent chance of genotype tt:
- Number of tt = 0
- Total = 4
- Probability = (0/4) * 100% = 0%
-
Probability of the phenotype of brown eyes:
- Genotypes expressing brown eyes include TT and Tt:
- Total = 2 (TT) + 2 (Tt) = 4
- Probability = (4/4) * 100% = 100%
-
Probability of the phenotype of blue eyes:
- Genotype expressing blue eyes is tt, which has 0 occurrences:
- Probability = (0/4) * 100% = 0%
In summary:
- TT = 50%
- Tt = 50%
- tt = 0%
- Brown eyes = 100%
- Blue eyes = 0%
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