To complete the statements:
The product of \( 6 \cdot \sqrt{3} \) represents the product of a rational number (6) and an irrational number (\(\sqrt{3}\)). The result of the product \( 6 \cdot \sqrt{3} \) is an irrational number.
So the completed statements are:
- The product of \( 6 \cdot \sqrt{3} \) represents the product of a rational number and an irrational number.
- The result of the product \( 6 \cdot \sqrt{3} \) is an irrational number.