17. A 60.-kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work is done against gravity by the student during the climb?

Question

Anonymous · Accepted Answer

2.4

Henry · Answer

Fs = mg = 60 kg * 9.8 N./kg = 588 N. = Weight or force of student. W = F*d = 588 * 4 = 2352 Joules.

Alex · Answer

566

Anonymous · Answer

jkjk

ocie · Answer

FS = MG = 60Kg X 9.8 N/Kg x 4 = 588 x 4= 2352 or 2400 Joules

Negus · Answer

LMAO HE ASKED THE QUESTION IN 2012