Asked by Michael

a rocket of mass 1000kg containing a propellant gas of 3000kg is to be launched vertically. If the fuel is consumed at a steady rate of 60kg per seconds, calculate the least velocity of the exhaust gas if the rocket and content will just lift off the launching pad immediately after firing?

Answers

Answered by Damon
F = d momentum/dt = mass/second * v
so
F = 60 kg/s * v
= m g = (1000+3000) (9.81)
so
v = 4000*9.81 / 60
Answered by bobpursley
force=thrust=mg
massrate*v=mg
60kg/sec*v=4000kg*9.8N/kg
solve for v
Answered by Rocket
A rocket of mass 1000kg contaning a propellant gas of 3000kg
Answered by Rocket
1000AND3000
Answered by ABEKE
Ft=M(V-U). Divide all by T. F=M\T(∆V). Mass one=1000kg Mass two =3000kg. Total mass =1000+3000=4000kg. Acceleration =10m\s^2.Force =M×A=4000×10=40000. Rate=M\T=60kg\s. 40000=60(∆V). Velocity =666•67m\s.
Answered by Muhammad
F=d/dt
Mg=d/dt
4000*10=60v
v=666.7
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