Asked by Michael
a rocket of mass 1000kg containing a propellant gas of 3000kg is to be launched vertically. If the fuel is consumed at a steady rate of 60kg per seconds, calculate the least velocity of the exhaust gas if the rocket and content will just lift off the launching pad immediately after firing?
Answers
Answered by
Damon
F = d momentum/dt = mass/second * v
so
F = 60 kg/s * v
= m g = (1000+3000) (9.81)
so
v = 4000*9.81 / 60
so
F = 60 kg/s * v
= m g = (1000+3000) (9.81)
so
v = 4000*9.81 / 60
Answered by
bobpursley
force=thrust=mg
massrate*v=mg
60kg/sec*v=4000kg*9.8N/kg
solve for v
massrate*v=mg
60kg/sec*v=4000kg*9.8N/kg
solve for v
Answered by
Rocket
A rocket of mass 1000kg contaning a propellant gas of 3000kg
Answered by
Rocket
1000AND3000
Answered by
ABEKE
Ft=M(V-U). Divide all by T. F=M\T(∆V). Mass one=1000kg Mass two =3000kg. Total mass =1000+3000=4000kg. Acceleration =10m\s^2.Force =M×A=4000×10=40000. Rate=M\T=60kg\s. 40000=60(∆V). Velocity =666•67m\s.
Answered by
Muhammad
F=d/dt
Mg=d/dt
4000*10=60v
v=666.7
Mg=d/dt
4000*10=60v
v=666.7
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