Question
a square painting is surrounded by a frame. the outside edges of the frame are x inches in length and the frame is 1 inch thick. what is the total area of the frame?
A: -4x + 4**??**
B: 4x - 4
C: x^2 + 4x + 4
D: x^2 - 4x - 4
A: -4x + 4**??**
B: 4x - 4
C: x^2 + 4x + 4
D: x^2 - 4x - 4
Answers
Damon
area of square outside frame = x^2
area of painting inside frame = (x-2)^2
so
x^2 - (x^2 -4 x + 4)
= 4 x -4
area of painting inside frame = (x-2)^2
so
x^2 - (x^2 -4 x + 4)
= 4 x -4
BemoGeno
thank you ^^