Asked by Aline
1) Stephanie earned $x while working 10 hrs. Evelyn earned $y while working 29hrs. If they both earn the same hourly wage and x+y=60, how many dollars did Stephanie earn?
2)the difference of the areas of two circles is 21pi. If their radio are r+3 and r, find the radius of the larger circle.
^144(pi)
3) The figure with a length of 5, width of 4, and hight of 3. (Rectangular box) what is the longes length of a diagonal of one of the faces?
2)the difference of the areas of two circles is 21pi. If their radio are r+3 and r, find the radius of the larger circle.
^144(pi)
3) The figure with a length of 5, width of 4, and hight of 3. (Rectangular box) what is the longes length of a diagonal of one of the faces?
Answers
Answered by
Reiny
steph;s wage = x/10
eve;a wage = y/29
but you said:
x/10=y/29
10y=29x
y = 29x/10
sub that into x+y=60 and solve
2.
area of large circle = π(r+3)^2
area of small circle = πr^2
π(r+3)^2 - πr^2 = 21π
divide by π(the r^2 drops out)
3. make a sketch and really think about it
Hint: Pythagoras
eve;a wage = y/29
but you said:
x/10=y/29
10y=29x
y = 29x/10
sub that into x+y=60 and solve
2.
area of large circle = π(r+3)^2
area of small circle = πr^2
π(r+3)^2 - πr^2 = 21π
divide by π(the r^2 drops out)
3. make a sketch and really think about it
Hint: Pythagoras
Answered by
Steve
x/10 = (60-x)/29
dividing out the pi,
(r+3)^2 - r^2 = 21
pick the two longest edges, then
d^2 = 5^2+4^2
dividing out the pi,
(r+3)^2 - r^2 = 21
pick the two longest edges, then
d^2 = 5^2+4^2
Answered by
Aline
Number two is 21/9?
Answered by
Steve
uh, no. You messed up the binomial expansion.
6r+9 = 21
6r+9 = 21
Answered by
Reiny
nope, not what I got
show me your steps to catch the error
show me your steps to catch the error
Answered by
Aline
ohh opps. Thank you
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