Asked by AGBOR
Draw the graph of the equation 4x²-6x+3 using the -2≤x≤3 use a scale of 2cm to 1unit on the x-axis, 1cm to 4units in the y-axis.
Find the graphfind;
(a) minimum value of y
(b) The roots of the equation 4x²-6x-3=0
(c) The value of x when y=5
(d) The solution set of the equation 4x²-6x-7=0
.
Please help please. I have plot the graph but I dbt know how to do the rest.
Find the graphfind;
(a) minimum value of y
(b) The roots of the equation 4x²-6x-3=0
(c) The value of x when y=5
(d) The solution set of the equation 4x²-6x-7=0
.
Please help please. I have plot the graph but I dbt know how to do the rest.
Answers
Answered by
Steve
did you graph it?
It should be easy to answer some of the questions using the graph.
(a) look at the vertex.
4x^2-6x+3 = (2x-3/2)^2 + 3/4
(b) use the quadratic formula
(c) just solve 4x^2-6x+3=5
(d) again use the QF
It should be easy to answer some of the questions using the graph.
(a) look at the vertex.
4x^2-6x+3 = (2x-3/2)^2 + 3/4
(b) use the quadratic formula
(c) just solve 4x^2-6x+3=5
(d) again use the QF
Answered by
Bosnian
Graphic solutions:
Use the graph.
a)
y = 4x²-6x+3
has its mimum value at :
xmin = 3 / 4
ymin = 3 / 4
b)
A vertical translation by 3 - ( - 3 ) = 3 + 3 = 6 units
Subtract 6 to each value of y.
The roots of the equation 4x²-6x-3=0
approx.
x = - 0.4 and x = 1.9
c)
y = 4x²-6x+3 = 5
approx.
x = - 0.3 and x = 1.8
d)
A vertical translation by 3 - ( - 7 ) = 3 + 7 = 10 units
Subtract 10 to each value of y.
The roots of the equation 4x²-6x-7=0
approx.
x = - 0.8 and x = 2.3
Use the graph.
a)
y = 4x²-6x+3
has its mimum value at :
xmin = 3 / 4
ymin = 3 / 4
b)
A vertical translation by 3 - ( - 3 ) = 3 + 3 = 6 units
Subtract 6 to each value of y.
The roots of the equation 4x²-6x-3=0
approx.
x = - 0.4 and x = 1.9
c)
y = 4x²-6x+3 = 5
approx.
x = - 0.3 and x = 1.8
d)
A vertical translation by 3 - ( - 7 ) = 3 + 7 = 10 units
Subtract 10 to each value of y.
The roots of the equation 4x²-6x-7=0
approx.
x = - 0.8 and x = 2.3
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