Asked by Anonymous

Points A and C on a map are 12 km apart if you follow a certain path. A troop of Boy Scouts leaves Point A at 11:00 a.m. They travel 3 km/hr because they have heavy packs until they reach Point B at 12:45. If they want to reach Point C by 2:00, how fast will they have to go in km/hr?

Answered by Steve
11:00 - 12:45 is 1 3/4 or 7/4 hours.
At 3 km/hr, that means they went

3 * 7/4 = 21/4 km
The remaining distance is thus 12 - 21/4 = 25/4 km

They only have 5/4 hrs left, so since speed = distance/time, they must travel at

(25/4)km / (5/4)hr = 5 km/hr

Sure hope they ate all their food to lighten their packs ...
Answered by bob
noice
Answered by Biff condomson
is dat china
Answered by Anonymous
What's the team average speed from point a to c
Answered by Akhil
12 - 21/4 = 27/4

(27/4)km / (5/4)hr = 5.4km/hr

Final answer is 5.4km/hr