Asked by sh
On a typical day at an ocean port, the water has a maximum depth of 20m at 8:00AM. The minimum depth of 8m occurs 6.2h later. Assume that the relation between the depth of the water and time is a sinusoidal function.
write an equation for the depth of the water at any time, t hours
I got h=6cos(2pi((t-8)/12.4))+14
how do I get the equation for sin?
I got h=6sin(2pi((t-9.8)/12.4))+14
since the highest point is at 8:00AM, and calculated the lowest point would be at 1:48AM(1.8@x-axis). Then I did 1.8+8 = 9.8 for the phase shift
but the back of the book says
h=6sin(2pi((t-4.9)/12.4))+14
thanks in advance
write an equation for the depth of the water at any time, t hours
I got h=6cos(2pi((t-8)/12.4))+14
how do I get the equation for sin?
I got h=6sin(2pi((t-9.8)/12.4))+14
since the highest point is at 8:00AM, and calculated the lowest point would be at 1:48AM(1.8@x-axis). Then I did 1.8+8 = 9.8 for the phase shift
but the back of the book says
h=6sin(2pi((t-4.9)/12.4))+14
thanks in advance
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