assuming no friction.
breaking weight up into components, parallel to plane, normal to plane
Fp=mg*sinTheta
Fn=mg*cosTheta
without friction, Fp is the operating up/down plane.
Net force=m*a
30N-mg*SinTheta=m*a
so solve for a.
then,
Vf^2=2*a*d solve of Vf
Starting from rest, a rope with a tension 30 N pulls a 2.0 kg box up a 2.0 m long, 30 degree smooth incline. What is the speed of the box at the top?
Please show steps! Thanks
1 answer