Asked by Juan
A daredevil is shot out of canon at 40°above the horizontal with a speed of 25.0 m/s. If the net is located 2.00 m higher than the launch point, what is the horizontal distance to the net if it is to safely catch the daredevil?
Answers
Answered by
bobpursley
time in air:
hf=hi+V*sinTheta*t-1/2 g t^2
hi=0, solve for time t. Use the quadratic equaiton.
Now with time t,
hordistance=V*cosTheta*t
hf=hi+V*sinTheta*t-1/2 g t^2
hi=0, solve for time t. Use the quadratic equaiton.
Now with time t,
hordistance=V*cosTheta*t
Answered by
Juan
65m?
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