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Cia
How can I evaluate the integral of xln(x)dx by using integration by parts
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Answered by
Steve
u = lnx
du = 1/x dx
dv = x dx
v = 1/2 x^2
∫u dv = uv - ∫v du, so
∫x lnx dx = 1/2 x^2 lnx - ∫(1/2 x^2)(1/x dx)
= 1/2 x^2 lnx - 1/2 ∫x dx
...
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