Asked by Cia
How can I evaluate the integral of xln(x)dx by using integration by parts
Answers
Answered by
Steve
u = lnx
du = 1/x dx
dv = x dx
v = 1/2 x^2
∫u dv = uv - ∫v du, so
∫x lnx dx = 1/2 x^2 lnx - ∫(1/2 x^2)(1/x dx)
= 1/2 x^2 lnx - 1/2 ∫x dx
...
du = 1/x dx
dv = x dx
v = 1/2 x^2
∫u dv = uv - ∫v du, so
∫x lnx dx = 1/2 x^2 lnx - ∫(1/2 x^2)(1/x dx)
= 1/2 x^2 lnx - 1/2 ∫x dx
...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.