Asked by joy

Can somebody shows me step by step with numbers on how to calculate the period for this question-equation. A black hole is an object with mass, but no spatial extent. It truly is a particle. A black hole may form from a dead star. Such a black hole has a mass several times the mass of the Sun. Imagine a black hole whose mass is eighty-two times the mass of the Sun.Use the equation T^2=((4π^2)/GM)a^3 to calculate this period.
I think this is Kepler third law equation.
Answered by Steve
well, it looks like M is 82*sunmass
find the values for that and G and a and then just plug them in. I assume you can do that much...
Answered by joy
do you know what is a equal to. I know everything else except for a.
Answered by Steve
clearly you did not make the effort to look up the law. a is the semi-major axis of the elliptical orbit.
Answered by joy
i still don't know what the value for a is.I look up on google and it is the distance in AU and this question doesn't give what is the value for a.
Answered by Dr. Neutron
You use the wrong equation. Use this equation square root (a^3/M) and you will get the answeranswer equal to .110yr
ais1 and M is 82kg
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