Asked by Andrea
Suppose A is directly proportional to the square of B,and A=45 when B=3.
a)Find the constant of proportionality
b)Write the formula for A in terms of B
c)Use your formula to find A when B=6
a)Find the constant of proportionality
b)Write the formula for A in terms of B
c)Use your formula to find A when B=6
Answers
Answered by
Scott
A = k B^2
a) 45 = k * 3^2 ... k = ?
b) A = ? B^2
c) A = ? * 6^2
a) 45 = k * 3^2 ... k = ?
b) A = ? B^2
c) A = ? * 6^2
Answered by
Namrata shakya
Given
A=45 , B = 3
A∝B^2
That means A= k B^2
Where k is proportionality sign
a) 45 = 9 k
k = 5 ( constant of proportionality)
b) A = 5 B^2
c) when B =6 A=?
A = 36×5
A= 180
I hope it will help you.
A=45 , B = 3
A∝B^2
That means A= k B^2
Where k is proportionality sign
a) 45 = 9 k
k = 5 ( constant of proportionality)
b) A = 5 B^2
c) when B =6 A=?
A = 36×5
A= 180
I hope it will help you.
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