Asked by Mariam
A pellet is fired through two circular plates .8 m apart, both rotating at -95rad/s. The angular displacement of second bullet hole is 82° from the first bullet hole. Calculate the bullet’s speed in m/s.
If someone could help me see where to insert the factors in whichever equation that would be very helpful. I'm stuck!
If someone could help me see where to insert the factors in whichever equation that would be very helpful. I'm stuck!
Answers
Answered by
bobpursley
The second plate traveled 82deg
displacement=speed*time
82deg*PIrad/180deg=95rad/sec*time
time= 82*PI/180 / 95=.0150 sec
speed bullet= distance/time=.8m/.0150=53.3m/s
displacement=speed*time
82deg*PIrad/180deg=95rad/sec*time
time= 82*PI/180 / 95=.0150 sec
speed bullet= distance/time=.8m/.0150=53.3m/s
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