Asked by Mariam
Can someone help me do this? I'm not sure where to insert the numbers nor in which equation.
The tires on your truck have 0.35 m radius. In a straight line, you drive 2600 m. What is the angular displacement of the tire, during this trip? Would the angular displacement be more or less if you put on big mud tires with a radius of .60m
The tires on your truck have 0.35 m radius. In a straight line, you drive 2600 m. What is the angular displacement of the tire, during this trip? Would the angular displacement be more or less if you put on big mud tires with a radius of .60m
Answers
Answered by
Anonymous
every 2 pi radians or 360 degrees you go one circumference which is 2 pi R meters
2600 = 2 pi R n when n is the number of turns of the wheel
n = 2600 /(2 pi R)
total angle in degrees = 360 n
total angle in radians = 2600/R
bigger tire is bigger R which is less n
2600 = 2 pi R n when n is the number of turns of the wheel
n = 2600 /(2 pi R)
total angle in degrees = 360 n
total angle in radians = 2600/R
bigger tire is bigger R which is less n
Answered by
bobpursley
circumference = 2 PI*radius
displacementrotations=distane/circumference
displacment angle= rotations*2PI
= distance*2PI/2PIr radians= distance/r radians
2600/.35 radians
displacementrotations=distane/circumference
displacment angle= rotations*2PI
= distance*2PI/2PIr radians= distance/r radians
2600/.35 radians
Answered by
Henry
Circumference = 2pi*r = 6.28 * 0.35 = 2.2 m.
Disp. = 2600m * 6.28rad/2.2m = 7422 rad.
Circumference = 6.28 * 0.6 = 3.77 m.
Disp. = 2600m * 6.28rad/3.77m = 4331 rad.
Disp. = 2600m * 6.28rad/2.2m = 7422 rad.
Circumference = 6.28 * 0.6 = 3.77 m.
Disp. = 2600m * 6.28rad/3.77m = 4331 rad.
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