Question

What is the loop that forms after many iterations when the initial value of g is 1.72?
g(x)= -2|x-2|+4

I tried to do this but it isn't looping so I think I'm doing it wrong. Help!

Answer 1

It "loops" again at iteration ^13; where you get 2.24, likewise at iteration ^3. And again at iteration ^14, where you get 3.52, likewise at ^4. I am unsure if this is the definition of the "loop". My book doesn't explain if a loop is where you keep getting the same number after a certain iteration, or you will "loop" back around the iteration and then keep going? Can you please tell me if I'm right? Thank you in advance.

Answer 2

Not sure what you want. Do you mean that g is replaced by the previous value of g, so that

g(n+1) = -2|g(n)-2|+4

??
Otherwise, how do you get any looping activity?

Answer 3

4 years and one day later, my best answer is to do loop-de-loops on a rollercoaster. math sucks