Question

Marisa spent 3/4 of her money on a necklace. She spent 1/2 of the remainder on earrings. The necklace cost $30.00 more than the earrings. How much did the necklace cost?

Answer 1

well first, let's make everything like terms, just to make things easier.
1/2 of 1/4 is 1/8.
3/4= 6/8

We also know that 6/8 is $30 more than 1/8
so:
6/8x = 1/8x + 30

Solve for x, then find the price of the necklace by multiplying 6/8 (aka 3/4) by x.

Answer 2

Marisa has $X.
Necklace: 3/4*x = $3x/4.
Bal. = X-3x/4 = x/4 Dollars.
Earrings:1/2 * x/4 = x/8.
Bal. = x/4-x/8 = x/8.

x/8 + (x/8+30) + x/8 = X.
3x/8 - X = -30,
5x/8 = 30,
X = 48.

Necklace cost = 3x/4 = 3*48/4 =

Earrings cost x/8 = 48/8 =








































































































































































































bal. =

Answer 3

For a bar model you could draw eight boxes because a common denominator of 3/4 and 1/2 is 8 or 4 but you would do eight boxes. Next, you could say that 6 boxes is how much money she spent on the necklace. Now, 1/2 of the remainder would be 1 box out of what is left. If the necklace cost $30 more than the earrings then you could do 6 - 1 which equals 5. Then $30 divided by 5. That means that there is 6 in each box. Then 6 x 6 is 36 so the necklace cost $36.