Asked by Rilwan
A thread of mercury of length 15cm is used to trap some air in a capillary tube with uniform cross sectional area and closed at one end.With the tube vertical and the open end uppermost,the length of the trapped air column is 20cm.calculate the length of the air column when the tube is held(!)horizontally (!!)vertically with the open end underneath.atmospheric pressure =76cm of mercury
Answers
Answered by
Damon
at the start air pressure in bottom of tube = 76 + 15 = 91 cm Hg
when horizontal the pressure will be 76+0 = 76 cm
P2 V2 = P1 V1 since n and R and T are the same
20 * 91/76 = 23.9
when upside down
Pair = 76 - 15 = 61 cm Hg
20 * 91/61 = 29.8
when horizontal the pressure will be 76+0 = 76 cm
P2 V2 = P1 V1 since n and R and T are the same
20 * 91/76 = 23.9
when upside down
Pair = 76 - 15 = 61 cm Hg
20 * 91/61 = 29.8
Answered by
Ayeesha
What if an atmospheric pressure is not given
Answered by
Ada
The atmospheric pressure is constant. Whether it is given or not, you should have it in mind
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