Question
Find the indicated term in the expansion of the given binomial.
The term that does not contain x in the expansion of
(6x+1/2x)^12
Is there an easier way to find the answer instead of going through finding 13 terms
Thanks.
The term that does not contain x in the expansion of
(6x+1/2x)^12
Is there an easier way to find the answer instead of going through finding 13 terms
Thanks.
Answers
When 'x' is not in the term, than x will have the same power in the numerator and denominator, and will hence cancel out.
So, (6x) and (1/2x) will be raised to same power.
Which term will this happen in?
So, (6x) and (1/2x) will be raised to same power.
Which term will this happen in?
(a+b)^12
where is power of a same as of b
C(12,6) a^6 b^6
where b is binomial coef
C(12,6) = 12!/[6! 6!] = 12*11*10*9*8*7/6!
=2*11*3*2*7
=924
so
924[(6x)^6 * 1/(2x)^6 ]
924 * 6^6/2^6
where is power of a same as of b
C(12,6) a^6 b^6
where b is binomial coef
C(12,6) = 12!/[6! 6!] = 12*11*10*9*8*7/6!
=2*11*3*2*7
=924
so
924[(6x)^6 * 1/(2x)^6 ]
924 * 6^6/2^6
the 11th term? x can't be cancelled
Thanks Damon
the "center or middle" term ... 7th
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