Asked by y912f
Write the function in terms of the cofnction with an acute angle.
tan 18degrees
A. sec18deg
B. cot18deg
C. cot72deg
D. cot108deg
find a solution for the equation.
sin(2theta+20deg) = cos(3theta-5deg)
thnkks:))
tan 18degrees
A. sec18deg
B. cot18deg
C. cot72deg
D. cot108deg
find a solution for the equation.
sin(2theta+20deg) = cos(3theta-5deg)
thnkks:))
Answers
Answered by
bobpursley
draw a right triangle. Let A and B be the acute angles. Isn't tanA=ctnB, so
tanA=ctn(90-A)
tanA=ctn(90-A)
Answered by
y912f
thnks..can you help me with the second one
find a solution for the equation.
sin(2theta+20deg=cos(3theta-5deg)
:)
find a solution for the equation.
sin(2theta+20deg=cos(3theta-5deg)
:)
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