Asked by Favour

Pls teach me how to evaluate sin 375° without using calculator
Answered by Bosnian
375°= 360° + 15°


sin ( 360° + θ ) = sin θ

sin 375° = sin ( 360° + 15° ) = sin 15°


15° = 60° - 45°


sin ( A + B ) = sin ( A ) cos ( B ) - cos ( A ) sin ( B )


sin 15° = sin ( 60° - 45° ) = sin ( 60° ) cos ( 45° ) - cos ( 60° ) sin ( 45° )

sin 15° = ( √3 / 2 ) ∙ ( √2 / 2 ) - ( 1 / 2 ) ∙ ( √2 / 2 )

sin 15° = √3 ∙ √2 / 2 ∙ 2 - 1 ∙ √2 / 2 ∙ 2

sin 15° = √3 ∙ √2 / 2 ∙ 2 - √2 / 2 ∙ 2

sin 15° = ( √3 ∙ √2 - √2 ) / 2 ∙ 2

sin 15° = √2 ∙ ( √3 - 1 ) / 2 ∙ 2

sin 15° = √2 ∙ ( √3 - 1 ) / √2 ∙ √2 ∙ 2

sin 15° = ( √3 - 1 ) / √2 ∙ 2

sin 15° = ( √3 - 1 ) / 2√2




Answered by Bosnian
My typo.

sin ( A - B ) = sin ( A ) cos ( B ) - cos ( A ) sin ( B )
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