Asked by Simon

Find the value of X if;
Log base 10 7+ log base 10(3x+2)-log base 10(2x-1)=1
Answered by Damon
log [7(3x+2)/(2x-1)]= 1
then
[7(3x+2)/(2x-1)] = 10^1 = 10
7(3x+2) = 20x-10
21 x + 14 = 20 x - 10
etc
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