Asked by Riya
Show that in a SIGN the phase difference between displacement and velocity is 90°and between displacement and acceleration is 180°
Answers
Answered by
Steve
that's SINE
s = sin(x)
v = ds/dx = cos(x) = sin(x+90°)
a = dv/dt = -sin(x) = sin(x+180°)
s = sin(x)
v = ds/dx = cos(x) = sin(x+90°)
a = dv/dt = -sin(x) = sin(x+180°)
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